矩阵交换行

markpan 2023-03-07 11:22:19 13 返回题目

#include using namespace std;

int main() { int a[5][5]; int m,n; for(int i = 0;i < 5;i++){ for (int j = 0; j < 5;j++){ cin >> a[i][j];
} } cin >> m >> n; int temp; //固定m ,n行 for(int j = 0;j < 5;j++){ temp = a[m-1][j]; a[m-1][j] = a[n-1][j]; a[n-1][j] = temp; }

for(int i = 0;i < 5;i++){
    for (int j = 0; j < 5;j++){
        cout << a[i][j] << " ";
    }
    cout << endl;
}    

return 0;

}

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