wurenchao 2022-09-12 18:38:59 6 返回题目
#include <bits/stdc++.h>
using namespace std;
int main() {
int n; cin >> n; for (int i = 23; i <= n; i += 5)//减少时间复杂度 if (i % 3 == 2 && i % 5 == 3 && i % 7 == 2) cout << i << endl; return 0;
}
